Delete all tuples from a list, if the first two elements of another tuple matches-CodePudding

i have two tuple lists, and i want to delete all tuples from list1, if the first two elements of a tuple from list2 matches with the first two elements of a tuple from list1.

list1 = [('google', 'data', '1'), ('google', 'data', '2'), ('google', 'data', '3'), ('google', 'data', '4'), ('google', 'WORLD', '1')]

list2 = [('google', 'data', '1'), ('google', 'HELLO', '2'), ('google', 'BLA', '3')]

Result: list1 = [('google', 'WORLD', '1')]

CodePudding user response：

You can use a list comprehension with all to get only elements that do not match with any of the elements from the second list.

res = [x for x in list1 if all(x[:2] != y[:2] for y in list2)]

CodePudding user response：

Take the first first two elements of each tuple in list2, use set() to deduplicate entries, then filter elements in list1 that are not in this set.

list1 = [('google', 'data', '1'), ('google', 'data', '2'), ('google', 'data', '3'),
         ('google', 'data', '4'), ('google', 'WORLD', '1')]
list2 = [('google', 'data', '1'), ('google', 'HELLO', '2'), ('google', 'BLA', '3')]

list2_pairs = set(map(lambda tpl: tpl[0:2], list2))
print(list2_pairs)  # {('google', 'BLA'), ('google', 'HELLO'), ('google', 'data')}
list1_result = list(filter(lambda tpl: tpl[0:2] not in list2_pairs, list1))
print(list1_result)  # [('google', 'WORLD', '1')]