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Vb how to implement on a particular column count, then list item in the most times

Time:09-18

For example:
1 a
2 b
3 c
4 a
5 a
6 b
Calculate a how many, in the second column is to realize the best
A 3
2 b
C 1
Excuse me, how to implement, need through SQL?

CodePudding user response:

The SELECT field 2, count (column 2) FROM table GROUP BY field 2;

CodePudding user response:

Your example happens to be the order of the descending order of count and data, generally available:

The SELECT field 2, count (column 2) FROM table GROUP BY field 2 ORDER BY count (column 2) DESC;

CodePudding user response:

A SQL statement can be achieved:
The select field, the count number (field) as the from table group by field
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