How to get the smallest number of an array with the exception of sentinel value?-CodePudding

I made a code, my only problem is that it displays the sentinel value (zero) as its smallest number.

How do I ignore the sentinel value when taking the smallest number?

for (int c = 0; c < lengthOfArray; c  ) {
    if(arr[c] < min)
        min = arr[c];             
             
    if (arr[c] > max)
       max = arr[c];      
}
             
System.out.println("Smallest:");
System.out.println(min);
System.out.println("Largest:");
System.out.println(max);

Below is my expected output:

(input:)
1 5 3 0

(output:)
Smallest:
 1
Largest:
5

However, my current code would always display 0 (zero) in the Smallest.

CodePudding user response：

Solution

You may add a condition on the value along woth min one :

if (arr[c] < min && arr[c] != 0)

Improve

You can iterate on values and not in index, code may be nicer :

int[] arr = new int[]{8, 6, 9, 0, 6, 8};
int min = Integer.MAX_VALUE, max = Integer.MIN_VALUE;

for (int val : arr) {
    if (val < min && val != 0)
        min = val;
    if (val > max)
        max = val;
}

System.out.println("Smallest: "   min); // Smallest: 6
System.out.println("Largest:"   max); // Largest:9

CodePudding user response：

just add an condition

for (int c = 0; c < lengthOfArray; c  ) {
  if(arr[c] != 0){

    if(arr[c] < min)
        min = arr[c];             
             
    if (arr[c] > max)
       max = arr[c];  

   }
}
             
System.out.println("Smallest:");
System.out.println(min);
System.out.println("Largest:");
System.out.println(max);

CodePudding user response：

There is another approach for solve your problem:

    IntSummaryStatistics arrSummaryStatistics = IntStream.of(arr)
            .summaryStatistics();

    System.out.println("Smallest:");
    System.out.println(arrSummaryStatistics.getMin());
    System.out.println("Largest:");
    System.out.println(arrSummaryStatistics.getMax());

CodePudding user response：

Another variant using IntStream and OptionalInt:

int[] nums = {1, 5, 3, 0};
OptionalInt min = IntStream.of(nums).filter(x -> x != 0).min();
OptionalInt max = IntStream.of(nums).filter(x -> x != 0).max();