I have following image url:

https://img.com/woo/image/u/f_auto,q_auto/w_350/v1619377072/Products/dada/Products/dada/IMG_47473065_IDW_IMAGE_bf30ac4dbbd308c8b0248b954a58a731a5b413b0f6782b834c781d0da621d727_HR.jpg

Here url containing by default resolution i.e. w_350 in it. I want to remove this resolution from this image url.

Final output of image url should be like this :

https://img.com/woo/image/u/f_auto,q_auto/v1619377072/Products/dada/Products/dada/IMG_47473065_IDW_IMAGE_bf30ac4dbbd308c8b0248b954a58a731a5b413b0f6782b834c781d0da621d727_HR.jpg

How can I do this?

Is there anything better than this?

re.sub(r"w_\d\d\d/", "", url)

CodePudding user response：

This is another approach: If you are sure the pattern will only contain digits 0-9 it's always better to use [0-9] rather than \d, as from the documentation:

\d Matches any Unicode decimal digit (that is, any character in Unicode character category [Nd]). This includes [0-9], and also many other digit characters. If the ASCII flag is used only [0-9] is matched.

Using [0-9] will reduce the computation as only the digit 0-9 will be matched and not all the Unicode characters.

import re
url = 'https://img.com/woo/image/u/f_auto,q_auto/w_350/v1619377072/Products/dada/Products/dada/IMG_47473065_IDW_IMAGE_bf30ac4dbbd308c8b0248b954a58a731a5b413b0f6782b834c781d0da621d727_HR.jpg'

url = re.sub(r'[a-z]_[0-9]{3}/', '', url)
print (url)

Output:

https://img.com/woo/image/u/f_auto,q_auto/v1619377072/Products/dada/Products/dada/IMG_47473065_IDW_IMAGE_bf30ac4dbbd308c8b0248b954a58a731a5b413b0f6782b834c781d0da621d727_HR.jpg

CodePudding user response：

I just tested and this worked

import re
pattern = "([a-z]_[0-9]{3}\/)"
original_string = "https://img.com/woo/image/u/f_auto,q_auto/w_350/v1619377072/Products/f6782b834c781d0da621d727_HR.jpg"
changed = re.sub(pattern, "", original_string)
#output   

should give you this value

"https://img.com/woo/image/u/f_auto,q_auto/v1619377072/Products/f6782b834c781d0da621d727_HR.jpg"