How to return exact match on first element in the list-CodePudding

I have list I need to append the into another list which matches
The exact match should come at first
then it matches related matched
if a = ['mnoabc', 'defabc', 'abc', 'abcdef', 'ijk', 'lmn'] I am searching 'abc' then 'abc' should come first then 'abcdef', then 'mnoabc', 'defabc'
Not worried ordering of about mnoabc', 'defabc'. if 'abc' is coming at start of the string then it should append to list at beginning

a = ['mnoabc', 'defabc', 'abc', 'abcdef', 'ijk', 'lmn']
m = []
for i in a:
    if 'abc' in i:
        m.append(i)
m

My out>> ['mnoabc', 'defabc', 'abc', 'abcdef']

Expected >> [ 'abc', 'abcdef','mnoabc', 'defabc']

Do i need to do regex for this?

CodePudding user response：

You can use insert to insert an item at a specified position. Try the following:

a = ['mnoabc', 'defabc', 'abc', 'abcdef', 'ijk', 'lmn']

m = []
num_startswith = 0

for i in a:
    if i == 'abc':
        m.insert(0, i)
        num_startswith  = 1
    elif i.startswith('abc'):
        m.insert(num_startswith, i)
        num_startswith  = 1
    elif 'abc' in i:
        m.append(i)

print(m) # ['abc', 'abcdef', 'mnoabc', 'defabc']

The variable num_startswith keeps track of where to insert a word that starts with abc.

CodePudding user response：

Using startswith() method we can check whether the string startswith substring 'abc'.

a = ['mnoabc', 'defabc', 'abc', 'abcdef', 'ijk', 'lmn']
m = []
for i in a:
    if i.startswith('abc'):
        m.append(i)
for i in a:
    if(i not in m):
        if 'abc'in i:
            m.append(i)
        
print(m) //['abc', 'abcdef', 'mnoabc', 'defabc']