Given the tuples : tuple1 = (3,5,16,35,75) and tuple2 = (1,19,28,44,64), I would like the output to be list5=[3, 1, 5, 19, 16, 28, 35, 44, 75, 64]. This is what I've done but I know this isn't the best way to do it.

list5 =[]
list5.append(tuple1[0])
list5.append(tuple2[0])
list5.append(tuple1[1])
list5.append(tuple2[1])
list5.append(tuple1[2])
list5.append(tuple1[3])
list5.append(tuple2[3])
list5.append(tuple1[4])
list5.append(tuple2[4])
print(list5)

CodePudding user response：

You can zip the two tuples then create a single list using a list comprehension.

>>> tuple1 = (3,5,16,35,75)
>>> tuple2 = (1,19,28,44,64)
>>> [i for j in zip(tuple1, tuple2) for i in j]
[3, 1, 5, 19, 16, 28, 35, 44, 75, 64]

If there is a chance the tuples are of uneven length you can use itertools.zip_longest instead of zip

>>> from itertools import zip_longest
>>> tuple1 = (3,5,16,35,75)
>>> tuple2 = (1,19,28,44,64,89,101)
>>> [i for j in zip_longest(tuple1, tuple2) for i in j if i is not None]
[3, 1, 5, 19, 16, 28, 35, 44, 75, 64, 89, 101]

CodePudding user response：

You can use itertools and zip to support tuples of arbitrary size -

list5 = list(itertools.chain(*[[t1, t2] for t1, t2 in zip(tuple1, tuple2)]))

Update Following the comments I think - list(chain(*zip(tuple1, tuple2))) is the most elegant way

CodePudding user response：

Using zip() is a common way to approach this but if one of the tuples is longer than the other, you'll need a bit of extra work:

tuple1 = (3,5,16,35,75,98,99,100)
tuple2 = (1,19,28,44,64)

list5  = [n for z in zip(tuple1,tuple2) for n in z]    # alternate values
list5  = [*tuple1[len(tuple2):],*tuple2[len(tuple1):]] # longer tuple

print(list5)
[3, 1, 5, 19, 16, 28, 35, 44, 75, 64, 98, 99, 100]

It possible to do it without using zip, but it's a bit more convoluted:

 list5  = [t[i] for i in range(max(len(tuple1),len(tuple2))) 
                for t in (tuple1,tuple2) if i<len(t)]