Home > Software engineering >  Make data to display in graph in python
Make data to display in graph in python

Time:10-09

I'm writing an API endpoint in Django Rest framework and want to make data for showing graph I have data like this which I get from the database.

data = [
{
    "name": "Test 3",
    "status": "Active",
    "count": 1
},
{
    "name": "Test 2",
    "status": "Failed",
    "count": 1
},
{
    "name": "Test",
    "status": "In Progress",
    "count": 85
},
{
    "name": "Test",
    "status": "Failed",
    "count": 40
},
{
    "name": "Test",
    "status": "Active",
    "count": 1
},
{
    "name": "Test",
    "status": "Success",
    "count": 218
},
{
    "name": "Test 2",
    "status": "Active",
    "count": 1
}]

and I want to make final graph data from above like this in order to show it in the graph.

    [
    "labels": ['Test', 'Test 2', 'Test 3'],
    "data": [
        {
            name: 'Active',
            data: [1, 1, 1]
        },
        {
            name: 'Failed',
            data: [40, 1, 0]
        },
        {
            name: 'Success',
            data: [218, 0, 0]
        },
        {
            name: 'In Progress',
            data: [85, 0, 0]
        }
    ]
]

I'm trying to make data in that way but I'm unable to make the correct format of data can anyone please help is there any built-in functions that I can use to make the data correct.

response = [
        {
            'labels': [],
            'data':[],
        }
    ]
    for row in data:
        if row['name'] not in response[0]['labels']:
            response[0]['labels'].append(row['name'])
            innerData = []
            for status in ['Active', 'Failed', 'Success', 'In Progress']:
                if status in row['status']:
                    innerData.append(row['count'])
                else:
                    innerData.append(0)
            response[0]['data'].append(
                {
                    'name': status,
                    'data': innerData,
                }
            )

CodePudding user response:

In order to get unique labels, set comprehension can be used. Then you can use defaultdict to from key:value pair as each status being key name and count being corresponding values.

from collections import defaultdict

data = [{"name": "Test 3", "status": "Active", "count": 1}, {"name": "Test 2", "status": "Failed", "count": 1}, {"name": "Test", "status": "In Progress", "count": 85},{"name": "Test", "status": "Failed", "count": 40},{"name": "Test", "status": "Active", "count": 1},{"name": "Test", "status": "Success", "count": 218}, {"name": "Test 2", "status": "Active", "count": 1}]

d = defaultdict(list)
labels = sorted({each['name'] for each in data})

for each in data:
    d[each['status']].append(each['count'])
# -> defaultdict(<class 'list'>, {'Active': [1, 1, 1], 'Failed': [1, 40], 'In Progress': [85], 'Success': [218]})

final_result = {'labels': labels, 'data': []}
for k, v in d.items():
    final_result['data'].append({'name': k, 'data': v})

final_result would look like:

{'labels': ['Test', 'Test 2', 'Test 3'], 'data': [{'name': 'Active', 'data': [1, 1, 1]}, {'name': 'Failed', 'data': [1, 40]}, {'name': 'In Progress', 'data': [85]}, {'name': 'Success', 'data': [218]}]}

In order to fill small sized lists with zeros, refer to this answer.

  • Related