regex Python: split CamelCase AND STOP IF there is space-CodePudding

All help is greatly appreciated folks I found a brilliant solution here How to do CamelCase split in python ,

re.sub('([A-Z][a-z] )', r' \1', re.sub('([A-Z] )', r' \1', string)).split()

However I need it to stop IF THERE is SPACE Example

t = 'YankeesMets' >>> ['Yankees', 'Mets']
tt = 'CubsWhite Sox' >>> ['Cubs', 'White'] (no more words after the first whitespace)

So, how do I change regex to STOP splitting CamelCase if it finds space?

CodePudding user response：

You can get the part of the string from its beginning to the first whitespace and apply your solution to that part of the string:

re.sub('([A-Z][a-z] )', r' \1', re.sub('([A-Z] )', r' \1', text.split()[0])).split()

See the Python demo, and the following demo below:

import re
l = ['CubsWhite Sox', 'YankeesMets']
for s in l:
    print(f"Processing {s}")
    first = s.split()[0]
    result = re.sub('([A-Z][a-z] )', r' \1', re.sub('([A-Z] )', r' \1', first)).split()
    print(result)

Output:

Processing CubsWhite Sox
['Cubs', 'White']
Processing YankeesMets
['Yankees', 'Mets']