Python get variables from string after decoding with cryptography-CodePudding

I'm programming an decryption on a file with sign-in information. When I decrypt it, I end up with the info in a string. This is the piece of code:

decrypted_message = encryption_type.decrypt(original)
testing = decrypted_message.decode("utf-8")
print("test: ", testing)

The output is:

test:  ip = "192.168.xxx.xxx", username = "xxx", password = "xxx"

How do i get the ip, username and password out off this string?

I can still change the output if it needs to be changed for a certain method. Also I use the decode because otherwise I end up with b' before the output (which I know is bytes but I don't know how to use).

CodePudding user response：

So I changed the plaintext before encryption to a json:

{"ip": "192.168.xx.xx", "username": "xx", "password": "xx"}

Now that it's a json, I was able to print the variables after a parse.

settings = json.loads(testing)
print(settings["ip"])

So I now have a solution for my project.

CodePudding user response：

If your string is literally as shown in your question the:

s = 'ip = "192.168.xxx.xxx", username = "xxx", password = "xxx"'
print(s.split()[2][1:-2])

CodePudding user response：

If your output really is a string, something like this would parse it:

a = 'ip = "192.168.xxx.xxx", username = "xxx", password = "xxx"'
parsed = dict(x.replace('"', "").split(" = ") for x in a.split(", "))
# {'ip': '192.168.xxx.xxx', 'username': 'xxx', 'password': 'xxx'}

But as noted in the comments you are much better off storing the data in json in the first place:

import json
s = json.dumps(dict(ip="192.168.1.1", username="me", pass="xx"))
encode(s) # dummy fn
decoded = json.loads(decode(s))
# decoded is a dict