I would like to ask for help in Linux. I have a main folder where are three subfolders with files.

I need to delete all files in the subfolders where the subfolder meet the conditions... the subfolder size is smaller than 5kb and the files in this subfolder are older than 5 minutes.

I did this, but I found it completely wrong.

find ./main/* -type 'f' -mmin  5 -size -5k -delete

Structure: Structure

Folder: Main -> Subfolders: first(2 files), second(2 files), third(2 files) see picture

And I would like to make an exception for the subfolder - "second". I mean these rules will not work on the "second" subfolder.

So I did this.

find ./main/* -type 'd' -size -5k -not -path "./main/second"

But I don't know how to implement the part where I use the condition for files(older than 5 minutes) and then these files will be deleted.

Thank you for any help.

I tried this code. But it's always else

#! /usr/bin/bash
d="./main/*"
f="./main/*"
z=0

if [ "$d" == TRUE ] && ["$f" == TRUE ]
then
    $z="find $d -type 'd' -size -5k $f -type 'f' -mmin  5 -delete"
    echo "$z"
else
    echo "nothing"
fi

and it is always else... :/

summarize: I need to create a bash script that checks all the subfolders in the main folder. And if it finds that a subfolder is less than 5kb in size. So the script checks the files in that subfolder to see if the files are older than 5 minutes and if all these conditions are met. This will delete all files from that subfolder.

CodePudding user response：

I need to delete all files in the subfolders where the subfolder meet the conditions... the subfolder size is smaller than 5kb and the files in this subfolder are older than 5 minutes.

find -size will not work on folders (at least not in the way you expect it to). You will have to use something like du for this.

Here is a script that should do what you want to achieve:

#!/usr/bin/env bash

# The main directory
maindir="./main"

# Get list of subdirs in maindir
readarray -t subdirs < <(find "${maindir}" -mindepth 1 -maxdepth 1 -type d -not -path "${maindir}/second" | sort)

# Process list of subdirs
for subdir in "${subdirs[@]}"; do

    # Determine size of subdir
    size=$(du -bs "${subdir}" | awk '{ print $1 }')

    # Skip subdirs that exceed 5k
    if (( ${size} > 5 * 1024 )); then
        echo "Skipping subdir '${subdir}' (size: ${size} bytes)"
        continue
    fi

    # Find and delete files in subdir older than 5 min
    echo "Deleting files in subdir '${subdir}'..."
    find "${subdir}" -type f -mmin  5 -delete

done

Previous answer before OP provided more details - leaving this as is for future reference:

Regarding your find command:

I need to delete all files in the subfolders where the subfolder meet the conditions... the subfolder size is smaller than 5kb and the files in this subfolder are older than 5 minutes.

This would be:

find ./main -type f -size -5k -mmin  5 -not -path "./main/second/*" -delete

Explanation:

• You want to delete files, thus you need to find files using -type f
• -path needs a wildcard to function properly

Regarding your Bash script code:

• [ "$d" == TRUE ] does a string comparison. You set d="./main/*", so you test for [ "./main/*" == "TRUE" ], which is never true as those are different strings (same for $f)
• If you want to actually run the find command, you need to do it like this: $z=$("find $d -type 'd' -size -5k $f -type 'f' -mmin 5 -delete"), but $z will be empty after this, as find does not print anything when -delete is used

If you want further advice, you need to provide more information about what your intentions are with the script - currently, this is not very clear (at least to me).