How can I pass a vector to a function handle of the same size , so that it automatically takes the f-CodePudding

Assume I have a vector A=[a1 a2 a3 ... an], and a defined function handle f=@(x1,x2,x3,..,xn), how can I input the vector to the function handle without explicitly writing f(A(1),A(2),...,A(n))? The code I am writing gives me different n for different situations, and it is not practical to manually input the function parameters because it is of variable size.

Example: I might get f=@(x,y)(x^2 y^2) and A=[1 2], I can say f(A(1),A(2)) and my problem is solved, but only if I have two variables. If I have f=@(x,y,z)(x^2 y^2 z^2) and A=[1 2 3], I should write f(A(1),A(2),A(3)).

This may be rephrased probably as how can I control the number of the "slots" in the function handle the way I want?

CodePudding user response：

You can go via a cell array

% Convert input array to a cell
A = num2cell( A );
% Deal the cell array to the inputs of f
f( A{:} );

Or you just write your function so that it indexes an array, rather than relying on multiple scalars, i.e. f=@(x,y)x y; becomes f=@(z)z(1) z(2);