Restructure request snippet into class OOP in Python-CodePudding

I've tested this snippet and get the result as expected:

import requests
import json
url = 'https://example.com/getlistitem'
headers= {
        'User-Agent': 'Mozilla/5.0', 
        'Referer': 'http://banggia.tvs.vn/',
        'content-type': 'text/json',
        'Content-Type': 'application/json;charset=utf-8'
    }

res=requests.get(url, headers = headers, timeout= 30).json()
print(res)

Now, I manage to convert it into class as this:

class getvps():
    url = 'https://example.com/getlistitem'
    headers= {
        'User-Agent': 'Mozilla/5.0', 
        'Referer': 'http://banggia.tvs.vn/',
        'content-type': 'text/json',
        'Content-Type': 'application/json;charset=utf-8'
    }
    
    def response(self):
        return requests.get(self.url, headers = self.headers, timeout= 30).json()
    

if __name__ == '__main__':
    
    print(getvps.response)

Unforturnately, the result was: <function getvps.response at 0x034527C8> I have just learned Python and OOP for a few days. Please guide me to learn more via this example. Thanks!

CodePudding user response：

Classes are blue prints to create objects, so first of all you need to create an instance of getvps class.

my_vps = getvps()

Then you can call response method on this object, remember for calling a method you should put () at the end of it so the last line of your code should looks like this:

print(my_vps.getvps())

By the way it is convention to name classes with capital letters:

class Getvps

Also there is no need to put () after class name, if your class doesn't inherit from a parent class. Finally it's better to define url and headers as object attribute rather than class variables