Merge list of dictionaries based on first element but add only one index in dictionary value-CodePudding

Given the following list of dictionaries:

[{'person_id': '10114', 'detail_info': [1286, 1]}, {'person_id': '10114', 'detail_info': [1286, 1]}, {'person_id': '10114', 'detail_info': [1286, 3]}]

I need this result:

[{'person_id': '10114', 'detail_info': [1286, 5]}]

I need to add the second element of each detail_info when merging.

CodePudding user response：

Assuming you want to merge on 'person_id' (if not, you can easily change the key):

out = {}
for d in l:
    key = d['person_id']
    if not key in out:
        out[key] = d
    else:
        out[key]['detail_info'][1]  = d['detail_info'][1]
out = list(out.values())

output:

[{'person_id': '10114', 'detail_info': [1286, 5]}]

input:

l = [{'person_id': '10114', 'detail_info': [1286, 1]},
     {'person_id': '10114', 'detail_info': [1286, 1]},
     {'person_id': '10114', 'detail_info': [1286, 3]}]