How to convert Nnumpy array to a dictionary in Python?-CodePudding

Hi guys how would I go on converting numpy arrays as such:

[[  8.82847075  -5.70925653]
 [  1.07032615  -1.77975378]
 [-10.41163742  -0.33042086]
 [  0.23799394   5.5978591 ]
 [  7.7386861   -4.16523845]]

To what I desire in Python 3.10. That includes having the keys and values rounded to the nearest integer:

{'9':-6, '1':-2, '-10':0, '0':6, '8':-4}

CodePudding user response：

dict(zip(*d.round().astype(int).T))
Out: {9: -6, 1: -2, -10: 0, 0: 6, 8: -4}

The data

d = np.array([[  8.82847075,  -5.70925653],
       [  1.07032615,  -1.77975378],
       [-10.41163742,  -0.33042086],
       [  0.23799394,   5.5978591 ],
       [  7.7386861 ,  -4.16523845]])

CodePudding user response：

The following should work

a = np.round(a)
d = dict(zip(a[:, 0].astype(str), a[:, 1]))

Note: Equal keys will merge.

CodePudding user response：

I would do this with a list comprehension:

import numpy as np 
data = np.array([[8.82847075,-5.70925653],[1.07032615,-1.77975378],[-10.41163742,-0.33042086],[0.23799394,5.5978591],[7.7386861,-4.16523845]])
data_dict = { int(round(x)):int(round(y)) for x,y in data}
data_dict
>>>{9: -6, 1: -2, -10: 0, 0: 6, 8: -4}

CodePudding user response：

Try using this function:

arrayToDictionary(x:list):
    tempDictionary = dict()
    for value in x:
        x = str(int(x[0]))
        y = int(x[1])
        tempDictionary[x] = y
    return tempDictionary

# then call the function using:
print(arrayToDictionary(yourarray))