I'm working on building a function that takes in a list of company descriptions and then outputs the most common 3-word phrases found in the list. I've been able to get it to the point where it outputs a dictionary of tuples constructed like this:
{('technology', 'company', 'provides'): 2,
('various', 'industries.', 'company'): 2,
('provides', 'software', 'solutions'): 2,
('life', 'health', 'insurance'): 2,...}
I'd like to convert this to a table/dataframe that concatenates the strings into a single value and then creates a separate column that would store the number of instances of the phrase.
The ideal output would be:
Phrase | Occurrence |
---|---|
technology company provides | 2 |
various industries company | 2 |
provides software solutions | 2 |
life health insurance | 2 |
I've tried using the following which combines the tuple into a string but it drops the number of occurrences:
# function that converts tuple to string
def join_tuple_string(descriptions) -> str:
return ' '.join(descriptions)
# joining all the tuples
result = map(join_tuple_string, descriptions)
# converting and printing the result
print(list(result))
Here is the output:
['technology company provides',
'provides software solutions',
'product suite includes', 'life health insurance',...]
How can I concatenate these values without losing the number of occurrences? I'd like to be able to export this to a CSV to review the full list.
CodePudding user response:
given:
din = {('technology', 'company', 'provides'): 2,
('various', 'industries.', 'company'): 2,
('provides', 'software', 'solutions'): 2,
('life', 'health', 'insurance'): 2}
In would proceed as follows:
def reportValues(d):
result = []
for ky, v in d.items():
result.append([' '.join(ky), v])
return result
result = reportValues(din)
for r in result:
print(f'{r[0]:25}\t{r[1]}')
which produces:
technology company provides 2
various industries. company 2
provides software solutions 2
life health insurance 2
CodePudding user response:
import pandas as pd
result = {('technology', 'company', 'provides'): 2,
('various', 'industries.', 'company'): 2,
('provides', 'software', 'solutions'): 2,
('life', 'health', 'insurance'): 2}
df = pd.DataFrame(result.items(), columns=['phrase', 'occurrence'])
df.phrase = df.phrase.str.join(' ')
print(df)
df.to_csv('phrases.csv', index=False)
the df
output:
phrase occurrence
0 technology company provides 2
1 various industries. company 2
2 provides software solutions 2
3 life health insurance 2
the csv file:
phrase,occurrence
technology company provides,2
various industries. company,2
provides software solutions,2
life health insurance,2