Finding earliest date after groupby a specific column-CodePudding

I have a dataframe that look like below.

  id     name   tag   location       date
   1     John    34     FL        01/12/1990
   1     Peter   32     NC        01/12/1990
   1     Dave    66     SC        11/25/1990
   1     Mary    12     CA        03/09/1990
   1     Sue     29     NY        07/10/1990
   1     Eve     89     MA        06/12/1990
   :      :      :      :              :
   n     John    34     FL        01/12/2000
   n     Peter   32     NC        01/12/2000
   n     Dave    66     SC        11/25/1999
   n     Mary    12     CA        03/09/1999
   n     Sue     29     NY        07/10/1998
   n     Eve     89     MA        06/12/1997

I need to find the location information based on the id column but with one condition, only need the earliest date. For example, the earliest date for id=1 group is 01/12/1990, which means the location is FL and NC. Then apply it to all the different id group to get the top 3 locations. I have written the code to do this for me.

#Get the earliest date base on id group
df_ear = df.loc[df.groupby('id')['date'].idxmin()]
#Count the occurancees of the location
df_ear['location'].value_counts()

The code works perfectly fine but it cannot return more than 1 location (using my first line of code) if they have the same earliest date, for example, id=1 group will only return FL instead FL and NC. I am wondering how can I fix my code to include the condition that if the earliest date is more than 1.

Thanks!

CodePudding user response：

Use GroupBy.transform for Series for minimal date per groups, so possible compare by column Date in boolean indexing:

df['date'] = pd.to_datetime(df['date'])

df_ear = df[df.groupby('id')['date'].transform('min').eq(df['date'])]