I've been trying to round a vector of a DataFrame using a lambda function. In my vector I also have string values, so I tried this code:

dff.apply(lambda x: round(x, 2) if (isinstance(x,float)))

But it raises a SyntaxError.

CodePudding user response：

Ternary statement in Python require else after the condition.

dff.apply(lambda x: round(x, 2) if (isinstance(x,float)) else x)

CodePudding user response：

There are two problems here:

1. tenary if-else missing the else statement. Like answered by user17242583.
2. dff.apply digest column by column, thus the isinstance(x,float) will not work for rounding. Use the vectorized numpy.round instead.

dff.apply( lambda x: np.round(x,2))