How can one extract duplicate paths from igraph and is there a more efficient way than the double loop in the example below?
By duplicate/multiple paths I mean that the result should contain both B1 -> B2a -> B3
and B1 -> B2b -> B3
. But my code does not yield that.
The data:
library(dplyr)
library(igraph)
d <- tribble(~input, ~output,
"A1", "A2",
"A2", "A3a",
"A2", "A3b",
"B1", "B2a",
"B1", "B2b",
"B2a", "B3",
"B2b", "B3")
My analysis:
g <- graph_from_data_frame(d, directed = TRUE)
(finals <- V(g)[degree(g, mode = "out") == 0])
(starts <- V(g)[degree(g, mode = "in") == 0])
res_collect <- vector("list", length(starts) * length(finals))
tmp <- 1
for (i_s in seq_along(starts)) {
for (i_f in seq_along(finals)) {
res <- tryCatch(
{
all_simple_paths(g, from = starts[[i_s]], to = finals[[i_f]])[[1]]
},
error = function(cond) {
message("failed at starts-nr=", i_s, ", finals-nr=", i_f); return(as.integer(NA))
}
)
res_collect[[tmp]] <- res
tmp <- tmp 1
}
}
The problem:
res_collect[!is.na(res_collect)]
# [[1]]
# 3/8 vertices, named, from 60df173:
# [1] A1 A2 A3a
#
# [[2]]
# 3/8 vertices, named, from 60df173:
# [1] A1 A2 A3b
#
# [[3]]
# 3/8 vertices, named, from 60df173:
# [1] B1 B2a B3
1 path is missing: B1 -> B2b -> B3.
CodePudding user response:
You can try the code below
unlist(
lapply(
decompose(g),
function(x) {
finals <- V(x)[degree(x, mode = "out") == 0]
starts <- V(x)[degree(x, mode = "in") == 0]
all_simple_paths(x, starts, finals)
}
),
recursive = FALSE
)
which gives
[[1]]
3/4 vertices, named, from fb6335c:
[1] A1 A2 A3a
[[2]]
3/4 vertices, named, from fb6335c:
[1] A1 A2 A3b
[[3]]
3/4 vertices, named, from fb6335c:
[1] B1 B2a B3
[[4]]
3/4 vertices, named, from fb6335c:
[1] B1 B2b B3