python last row recursive pascal triangle-CodePudding

I have to create a recursive function pascal(n) that returns the line n of a pascal triangle as a list ( so pascal(3) returns [1, 3, 3, 1])

So far I have

` def pascal(n):

if n==1: 
    return [[1]]
else:
    result=pascal(n-1)
    row=[1]
    last_row=result[-1]
    for i in range(len(last_row)-1):
        row.append(last_row[i] last_row[i 1])
    row =[1]
    result.append(row)
    return row`

But this results in the error

object of type 'int' has no len()

If i instead write ` def pascal(n):

if n==1: 
    return [[1]]
else:
    result=pascal(n-1)
    row=[1]
    last_row=result[-1]
    for i in range(len(last_row)-1):
        row.append(last_row[i] last_row[i 1])
    row =[1]
    result.append(row)
    return result`

And then call pascal(3)[-1], there is no problem. How can I fix this issue? Thanks

CodePudding user response：

You want pascal(n) to return the nth line as a list in Pascals triangle, but you are returning [[1]] instead of [1] for pascal(1).

Also, the "last_row", i.e the previous row corresponding to pascal(n) would be pascal(n-1) and not pascal(n-1)[-1]. In your code, result[-1] is pascal(n-1)[-1] which the last element (int) of the (n-1)th row, hence the error.

This would be your function after making the above 2 changes.

def pascal(n):
    if n == 0: 
        return [1]
    else:
        last_row = pascal(n-1)
        row = [1]
        for i in range(len(last_row)-1):
            row.append(last_row[i] last_row[i 1])
        row  = [1]
        return row