i use this to check if there is a 06 number in the string. the 06 number is always 10 numbers.

$string = "This is Henk 0612345678";

$number = preg_replace('/[^0-9.] /', '', $string);

echo $number;

This is working good, but when the string is

$string = "This is 12Henk 0612345678";

The number is 120612345678 I dont want the 12 into it, but 12 is not always the same in the string. How can i check only for a 10 digits number ?

Thanks

CodePudding user response：

This could help you

/([ \w] )(06[0-9. ]{8})/

the 1st () is the entire String before the 06 and the 2nd() is the Number starting with 06 and 8 digits.

The solution does not cover the case where a 06 comes before the number sequence

CodePudding user response：

Rather than replacing everything that's not what you want, try searching for what you do want with preg_match.

That makes it a lot easier to be specific:

• The number always starts 06, so you can hard-code that in your regex
• That's followed by exactly 8 more digits, which you can specify as [0-9]{8} or \d{8} ("d" for "digit")
• To avoid matching longer numbers, you can surround that with \b for "word break"

Put it together, and you get:

preg_match('/\b06\d{8}\b/', $string, $matched_parts);

This doesn't change $string, but gives you an array in $matched_parts containing the matched parts; see the preg_match documentation for a detailed explanation.