Replacing decayed array with a pointer to array resulting in segmentation fault-CodePudding

I was trying to loop through an array using pointers:

#include <iostream>
#include <iterator>

int main() 
{
    char name[]{ "Abhi" };

    for (char* ptr_c{ name }; ptr_c != (ptr_c   std::size(name));   ptr_c) {
        std::cout << *ptr_c;
    } 

    std::cout << "\n";
}

This results in: Error: Segmentation fault core dumped

However, in the for loop's condition testing:

 for (char* ptr_c{ name }; ptr_c != (ptr_c   std::size(name));   ptr_c)
                                     ^^^^^^

Replcaing ptr_c with name makes it work. Why? Shouldn't name decay to ptr_c anyway?

CodePudding user response：

ptr_c != ptr_c   std::size(name)

This condition is never false. If you add a non-zero number to a pointer, the resulting pointer will never equal the original pointer. Hence, the infinite loop overflows the array.

Shouldn't name decay to ptr_c anyway?

No. name always decays to a pointer to the first element. ptr_c only starts as the first element, but after the first iteration, it points to other elements.