Why does my array prints only the first element?-CodePudding

    double fun(int size) {

    double *arr = (double*)calloc(size, sizeof(double));
    assert(arr);
    for (int i = 0; i < size; i  ) {
        scanf_s("%lf", &arr[i]);
    }
    return *arr;
    
    
}
void main() {
    int size = 5;
    printf("%lf", fun(size));
}

trying to print my array using the main function, it prints only the 1st element from the array.. someone have an idea how to fix it?

CodePudding user response：

double fun(int size)

Consider what the function is returning. A single double. The line *arr will get the value of the first element in the arr pointer and return it. What I think you mean to do is iterate over each element in a pointer to a double returned by the function.

double *fun(int size) {

  double *arr = (double*)calloc(size, sizeof(double));
  assert(arr);
  for (int i = 0; i < size; i  ) {
    scanf_s("%lf", &arr[i]);
  }
  return arr;
}
void main() {
  int size = 5;
  double *arr = fun(size);
  for (int i = 0; i < size; i  ) {
    printf("%lf", arr[i]);
  }
}