C looping using EOF, how to read next line?-CodePudding

I'm facing an issue while trying to resolve a particular problem in C. User input must be read in encrypted form and the output must be the decrypted message, that is, it is a replacement cipher.The problem is that when I read the first input, the program loops printing the decrypted message, it doesn't ask to read other inputs.
I'm really confused about this as I was told that I should use EOF, something I'm not very knowledgeable about. I could even solve it another way, but I need to implement the EOF, and because I don't know that, I'm having difficulty solving the exercise.

I am aware that the code I created is not the best for the resolution, however, it might work if someone helps me with this loop issue.

Source Code

#include <stdio.h>
#include <string.h>

void alterChar(int i, char phrase[])
{
    for (i = 0; phrase[i] != '\0'; i  )
    {
        if (phrase[i] == '@')
        {
            phrase[i] = 'a';
        }
                
        if (phrase[i] == '&')
        {
            phrase[i] = 'e';
        }
                
        if (phrase[i] == '!')
        {
            phrase[i] = 'i';
        }
                
        if (phrase[i] == '*')
        {
            phrase[i] = 'o';
        }
                
        if (phrase[i] == '#')
        {
            phrase[i] = 'u';
        }
                
        printf("%s\n", phrase);
    }
}

int main()
{
    int i;
    char phrase[256];
    
    while (scanf("%[^\n]s", phrase) != EOF)
    {
        ///scanf(" %[^\n]s", phrase);
    
        alterChar(i, phrase);
    }
    
    return 0;
}

CodePudding user response：

i think just putting the printf outside of the loop help and use feof (fetch en of file) to know where you are.

#include <stdio.h>
#include <string.h>

void alterChar(char phrase[]) {
    for (int i = 0; phrase[i] != '\0'; i  ) {
        if (phrase[i] == '@') {
            phrase[i] = 'a';
        }

        if (phrase[i] == '&') {
            phrase[i] = 'e';
        }

        if (phrase[i] == '!') {
            phrase[i] = 'i';
        }

        if (phrase[i] == '*') {
            phrase[i] = 'o';
        }

        if (phrase[i] == '#') {
            phrase[i] = 'u';
        }
    }
    printf("%s\n", phrase);
}

int main() {
    char phrase[256];

    while (!feof(stdin)) {
        scanf(" %[^\n]s", phrase);
        alterChar(phrase);
    }

    return 0;
}