Scenario if in input numbers are repeat-CodePudding

Code:

n = int(input("Type n: "))

def some_function(n):
    numbers, numbers_sum = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0], 45
    while True:
        digit = n % 10
        n //= 10
        if digit in numbers:
            numbers.remove(digit)
            numbers_sum -= digit
        else:
            break
    return numbers_sum

print(some_function(n))

Program needs to print the sum of numbers that are not found in the input.

I covered the scenario when numbers are not repeating and for this scenario if the input is 234567890 output is 1 . But don't have an idea for scenario when numbers are repeating.Etc. if the input is 22334567890 or 223344556677889900 output still needs to be 1 but it's not.

P.S. I can't do it with strings. I know 0 doesn't make difference because we are doing with - and .

CodePudding user response：

the easier way to do it is to transform it to a string and do set operations

>>> n=22334567890
>>> numbers=set("123456789")
>>> numbers-set(str(n))
{'1'}
>>>

and then transform back to integers

>>> sum(map(int,{'1'}))
1
>>>

if you don't want the string conversion, just make a function that give you the digits of the numbers and do the same

>>> def digits(n): #this is a generator function
        if n==0:
            yield 0
        while n:
            n,d = divmod(n,10)
            yield d


>>> n=22334567890            
>>> numbers=set(range(10))
>>> numbers
{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
>>> list(digits(n))
[0, 9, 8, 7, 6, 5, 4, 3, 3, 2, 2]
>>> 
>>> numbers - set(digits(n))
{1}
>>> sum({1})
1
>>>

CodePudding user response：

I solved it.Code:

n, finish = int(input("Type n: ")), 0
dig_list, num_list = [], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

def sum(n):
    while n > 0:
        digit = n % 10
        n //= 10
        dig_list.append(digit)
    for i in range (0, 11):
        if i in dig_list:
            num_list.remove(i)
    return num_list

for e in (sum(n)):
    finish  = e

print(finish)

Purpose of code.

Explanation: First, we create 2 lists. The first one(dig_list) has no elements and there we are gonna put all digits of input(n). The second list is a list of numbers from 0 to 9(num_list). Then we put all digits of n in the first list.Then using for loop we go through the first list.If numbers from 0 to 9 are found in the first list we remove them from the second list. In the end, we save the sum( ) of the remaining elements of the second list to a variable sum.