How to check if a number has subscript in it in Python?-CodePudding

I have a string which is like: t = '²'

This throws my code off: int(t) with the error:

ValueError: invalid literal for int() with base 10: '²'

How do I detect if a string is a superscript and not a real integer?

I just want to cast a string number to int and get the integer. I want to make sure that the numbers I pass doesn't throw the above error.

I don't want to use try/except block.

CodePudding user response：

The is_digit method returns True for subscripts and superscripts. You can use a combination of int and is_digit to implement that:

def is_subscript(s):
    if s.isdigit():
        try:
            int(s)
        except ValueError:
            return True
    return False

Then

print(is_subscript('²'))   # Should print True
print(is_subscript('2'))   # Should print False

CodePudding user response：

You need to translate the string like this

SUP = str.maketrans("⁰¹²³⁴⁵⁶⁷⁸⁹","0123456789")
t = '²'
print(int(t.translate(SUP)))

CodePudding user response：

You can use .isdecimal() for testing. Unlike .isnumeric() and .isdigit(), it does not recognize '²', etc. as a digit:

"²".isdecimal()
# False
"2".isdecimal()
#True