Better way to create scala array from lines of a file-CodePudding

Considering a file with string on each lines, I want to create an array with each line of the file as an element of the array. I know I can do it like so:

import scala.io.Source

val path: String = "path/to/text/file.txt"
var array: Array[String] = new Array[String](0)

for (line <- Source.fromFile(path).getLines) {
    array : = line
}

But it's quite long and maybe not very optimal. I look on the web and didn't find any better way of doing it. Do you have a better way of creating such array using Array built-in methods I may have missed or using map or anything else ?

Thanks.

CodePudding user response：

Using getLines returns an Iteration, from which you can use toArray

val path: String = "path/to/text/file.txt"
val array: Array[String] = Source.fromFile(path).getLines.toArray

CodePudding user response：

On top of the answer by @TheFourthBird:

In your code you don't close the file. This might be ok for short programs, but in a long-lived process you should close it explicitly.

This can be accomplished by:

import scala.io.Source
import scala.util.{Try, Using}

val path: String = "path/to/text/file.txt"
val tryLines: Try[Array[String]] = Using(Source.fromFile(path))(_.getLines.toArray)

See What's the right way to use scala.io.Source?