How can I match element by element of list?-CodePudding

i'm trying to solve the problem of checking the distance between letters by looking at the alphabet. I described it in a dictionary. I gave "l = 10000" so that later I could easily distinguish the correct numerator. I think the idea itself is good, but it gives me the error "if abs (words [text [i] [j]] - words [text [i] [j 1]] <10): IndexError: string index out of range "

I will be grateful for every tip.

Code:

    words={'A':0,'B':1,'C':2,'D':3,'E':4,'F':5,'G':6,'H':7,'I':8,'J':9,'K':10,'L':11,'M':12,'N':13,'O':14,'P':15,'Q':16,'R':17,'S':18,'T':19,'U':20,'V':21,'W':22,'X':23,'Y':24,'Z':25,}
    text = ['XXUXXTYVXWA', 'YTWYVWUTYA', 'PUOMQVMRNOSNVONOQOQMPPMRTVRSVRUNMOUSVUOTTMNRVQX']
    l = 0
    t = []
    for i in range(0,len(text)):
        for j in range(0,len(text[i])):
            if abs(words[text[i][j]] - words[text[i][j 1]] < 10):
                l = l 1
            else:
                l = 10000
        t.append(l)
        l = 0
    print(t)

CodePudding user response：

The error is raised with the last iteration, when you want to compare the last letter with the letter after the last letter, which doesn't exist. Perhaps start at 1 and compare the current letter with the previous letter like this:

words={'A':0,'B':1,'C':2,'D':3,'E':4,'F':5,'G':6,'H':7,'I':8,'J':9,'K':10,'L':11,'M':12,'N':13,'O':14,'P':15,'Q':16,'R':17,'S':18,'T':19,'U':20,'V':21,'W':22,'X':23,'Y':24,'Z':25,}
    text = ['XXUXXTYVXWA', 'YTWYVWUTYA', 'PUOMQVMRNOSNVONOQOQMPPMRTVRSVRUNMOUSVUOTTMNRVQX']
    l = 0
    t = []
    for i in range(0,len(text)):
        for j in range(1,len(text[i])):
            if abs(words[text[i][j-1]] - words[text[i][j]] < 10):
                l = l 1
            else:
                l = 10000
        t.append(l)
        l = 0
    print(t)

CodePudding user response：

I would recommend using the ord built-in to check distance between letters.

In [1]: ord("i") - ord("g")
Out[1]: 2