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create a rule in R to count number of consultations per patient per day

Time:03-18

I have created the following dataset with key scenarios that I have in my actual dataset:

df <- data.frame (organisation_id  = c("1","1","2","2","2","2","2","2","3","3","3","3","3","4","4","4","4","4","4","4","4","4","4","4","4","4","4","4","4","4","4","4","4","4"),
                  patient_id = c("1230","1230","1222","1222","1244","1244","987","987","2223","2223","2247","2247","2247","1234","1234","1234","1234","1234","1234","1234","1234","1239","1239","1239","3322","3322","3322","5434","5434","4488","4488","4488","1250","1250"),
                  date = c("08-02-2018","08-02-2018","12-01-2018","12-01-2018","12-01-2018","22-02-2018","12-01-2018","22-02-2018","01-03-2019","01-03-2019","01-03-2019","01-03-2019","01-03-2019","12-07-2020","12-07-2020","12-07-2020","12-07-2020","12-07-2020","12-07-2020","12-07-2020","12-07-2020","13-07-2020","13-07-2020","13-07-2020","16-06-2021","16-06-2021","16-06-2021","14-05-2019","14-05-2019","17-03-2020","17-03-2020","17-03-2020","03-02-2019","03-02-2019"),
                  consultation_mode = c("Telephone","Face-to-Face","Telephone","Telephone","Face-to-Face","Face-to-Face","Telephone","Telephone","Home visit","Home visit","Face-to-Face","Face-to-Face","Face-to-Face","Telephone","Telephone","Telephone","Telephone","Face-to-Face","Face-to-Face","Face-to-Face","Face-to-Face","Home visit","Home visit","Home visit","Face-to-Face","Telephone","Face-to-Face","Telephone","Face-to-Face","Face-to-Face","Telephone","Telephone","Face-to-Face","Face-to-Face"),
                  professional_id = c("24","11","123","110","123","110","123","333","444","444","444","444","444","1133","12","25","26","12","34","35","38","44","44","5556","443","443","445","29","29","555","5556","12","1133","113663"),
                  professional_role = c("Doctor","Support","Doctor","Support","Doctor","Support","Doctor","Nurse","Doctor","Doctor","Doctor","Doctor","Doctor","Support","Support","Nurse","Nurse","Support","Doctor","Doctor","Nurse","Nurse","Nurse","Doctor","Doctor","Doctor","Doctor","Doctor","Doctor","Doctor","Doctor","Support","Support","Support"),
                  professional_name = c("Dr John Taylor","Mary Wright","Dr Patricia Jones","James Davies","Dr Patricia Jones","James Davies","Dr Patricia Jones","Peter Hall","Dr Mary Wilson","Dr Mary Wilson","Dr Mary Wilson","Dr Mary Wilson","Dr Mary Wilson","Mary Wright","Anthony Patel","Jennifer Walker","Jennifer Walker","Anthony Patel","Dr Carol Bell","Dr Carol Bell","Deborah Dixon","Kevin R Collins","Kevin Collins","Dr Robert Brown","Dr Mary Wilson","Dr Mary Wilson","Dr John Snow","Dr John Taylor","Dr John Taylor","Dr James Smith","Dr Robert Brown","Anthony Patel","Mary Wright","Mary TEST Wright")
)

df$organisation_id <- as.factor(df$organisation_id)
df$patient_id <- as.factor(df$patient_id)
df$date <- as.Date(df$date, "%d-%m-%Y")
df$consultation_mode <- as.factor(df$consultation_mode)
df$professional_id <- as.factor(df$professional_id)
df$professional_role <- as.factor(df$professional_role)

I want to create two extra columns (include? and Nr_consultations_per_Pt_day) as per the below:

For each organisation_id, patient_id, date and consultation_mode check:

1- If there is only 1 row, include? = 1 and Nr_consultations_per_Pt_day = 1 for that professional_role.

2- If there is more than 1 row, include? = 1 for each different professional_id and professional_name with consultation_role = 'Doctor' or 'Nurse'.

Note: if there are 2 entries for ‘Doctor’ or ‘Nurse’ with different professional_id but same professional_name, the first row gets include? = 1 and the following rows include? = 0. E.g. 25 / 26 IDs for Jennifer Walker. Similarly, if there are 2 entries for ‘Doctor’ or ‘Nurse’ with same professional_id but different professional_name, the first row gets include? = 1 and the following rows include? = 0. E.g. 44 ID for Kevin R Collins / Kevin Collins.

2.1- If there is 0 'Doctor' or 'Nurse' (all ‘Support’), then the first row gets include? = 1 and the following rows include? = 0, with Nr_consultations_per_Pt_day = 1 for that professional_role.

Intermediate dataset:

organisation_id patient_id date consultation_mode professional_id professional_role professional_name include?
1 1230 08-02-2018 Telephone 24 Doctor Dr John Taylor 1
1 1230 08-02-2018 Face-to-Face 11 Support Mary Wright 1
2 1222 12-01-2018 Telephone 123 Doctor Dr Patricia Jones 1
2 1222 12-01-2018 Telephone 110 Support James Davies 0
2 1244 12-01-2018 Face-to-Face 123 Doctor Dr Patricia Jones 1
2 1244 22-02-2018 Face-to-Face 110 Support James Davies 1
2 987 12-01-2018 Telephone 123 Doctor Dr Patricia Jones 1
2 987 22-02-2018 Telephone 333 Nurse Peter Hall 1
3 2223 01-03-2019 Home visit 444 Doctor Dr Mary Wilson 1
3 2223 01-03-2019 Home visit 444 Doctor Dr Mary Wilson 0
3 2247 01-03-2019 Face-to-Face 444 Doctor Dr Mary Wilson 1
3 2247 01-03-2019 Face-to-Face 444 Doctor Dr Mary Wilson 0
3 2247 01-03-2019 Face-to-Face 444 Doctor Dr Mary Wilson 0
4 1234 12-07-2020 Telephone 1133 Support Mary Wright 0
4 1234 12-07-2020 Telephone 12 Support Anthony Patel 0
4 1234 12-07-2020 Telephone 25 Nurse Jennifer Walker 1
4 1234 12-07-2020 Telephone 26 Nurse Jennifer Walker 0
4 1234 12-07-2020 Face-to-Face 12 Support Anthony Patel 0
4 1234 12-07-2020 Face-to-Face 34 Doctor Dr Carol Bell 1
4 1234 12-07-2020 Face-to-Face 35 Doctor Dr Carol Bell 0
4 1234 12-07-2020 Face-to-Face 38 Nurse Deborah Dixon 1
4 1239 13-07-2020 Home visit 44 Nurse Kevin R Collins 1
4 1239 13-07-2020 Home visit 44 Nurse Kevin Collins 0
4 1239 13-07-2020 Home visit 5556 Doctor Dr Robert Brown 1
4 3322 16-06-2021 Face-to-Face 443 Doctor Dr Mary Wilson 1
4 3322 16-06-2021 Telephone 443 Doctor Dr Mary Wilson 1
4 3322 16-06-2021 Face-to-Face 445 Doctor Dr John Snow 1
4 5434 14-05-2019 Telephone 29 Doctor Dr John Taylor 1
4 5434 14-05-2019 Face-to-Face 29 Doctor Dr John Taylor 1
4 4488 17-03-2020 Face-to-Face 555 Doctor Dr James Smith 1
4 4488 17-03-2020 Telephone 5556 Doctor Dr Robert Brown 1
4 4488 17-03-2020 Telephone 12 Support Anthony Patel 0
4 1250 03-02-2019 Face-to-Face 1133 Support Mary Wright 1
4 1250 03-02-2019 Face-to-Face 113663 Support Mary TEST Wright 0

Final dataset: Example for one organisation_id,patient_id,date and for each category of consultation_mode and professional_role.

organisation_id patient_id date consultation_mode professional_role Nr_consultations_per_Pt_day
1 1230 08-02-2018 Face-to-Face Doctor 0
1 1230 08-02-2018 Face-to-Face Nurse 0
1 1230 08-02-2018 Face-to-Face Support 1
1 1230 08-02-2018 Telephone Doctor 1
1 1230 08-02-2018 Telephone Nurse 0
1 1230 08-02-2018 Telephone Support 0
1 1230 08-02-2018 Home visit Doctor 0
1 1230 08-02-2018 Home visit Nurse 0
1 1230 08-02-2018 Home visit Support 0

etc.

Any ideas on how to do this in R in an efficient way?

CodePudding user response:

If I understand your description correctly, for each row we want to evaluate the following conditions to decide whether include? = 1:

  1. The row's group size for organisation_id-patient_id-date-consultation_mode is 1
  2. The row's group size for organisation_id-patient_id-date-consultation_mode is greater than 1 AND the row corresponds to a:
    1. Doctor AND is the first among doctors with the same id/name
    2. Nurse AND is the first among nurses with the same id/name
    3. Support AND is the first among support AND is part of a organisation_id-patient_id-date-consultation_mode group that has no doctor or nurse

This logic will create the "intermediate" table. To create the "final" table, we go through each category of consultation_mode and professional_role and set Nr_consultations_per_Pt_day = 1 if there's a corresponding entry with include? = 1.

Based on the above expectation, here's how I'd do it:

library(tidyverse)

# For each row, add the size of its 
# organisation_id-patient_id-date-consultation_mode group
df2 <- df %>% group_by(organisation_id, patient_id, date, consultation_mode) %>% 
    mutate(group_size = n()) %>% ungroup()

# For each row, indicate whether it's the first entry of 
# organisation_id-patient_id-date-consultation_mode-professional_role group 
# of people with the SAME NAME but possiblly different ID
df3 <- df2 %>% group_by(organisation_id, patient_id, date, consultation_mode, 
        professional_role, professional_name) %>% 
    mutate(first_by_name = row_number()==1) %>% 
    ungroup()

# For each row, indicate whether it's the first entry of 
# organisation_id-patient_id-date-consultation_mode-professional_role group 
# of people with the SAME ID but possiblly different name
df4 <- df3 %>% group_by(organisation_id, patient_id, date, consultation_mode, 
        professional_role, professional_id) %>% 
    mutate(first_by_id = row_number()==1) %>% 
    ungroup()

# For each row, indicate whether there's no doctor/nurse in its 
# organisation_id-patient_id-date-consultation_mode
# and indicate the first entry in such support-only group
df5 <- df4 %>% group_by(organisation_id, patient_id, date, consultation_mode) %>% 
    mutate(support_only_group = length(intersect(professional_role, c("Doctor", "Nurse"))) == 0) %>% 
    mutate(first_in_support_only = row_number()==1 & support_only_group) %>% 
    ungroup()

# Apply rules to determine the inclusion status of each row
df6 <- df5 %>% mutate(`include?` = if_else(
        group_size == 1 | 
        (professional_role %in% c("Doctor","Nurse") & (first_by_name & first_by_id)) |
        first_in_support_only, 1, 0)) 
df6

enter image description here

Convert into the final table:

# Convert into the final table
df7 <- df6 %>% 
    select(-c(group_size, first_by_name, first_by_id, support_only_group, first_in_support_only)) %>% 
    group_by(organisation_id, patient_id, date) %>% 
    expand(consultation_mode, professional_role) %>%
    left_join(df6) %>%
    mutate(Nr_consultations_per_Pt_day = replace_na(`include?`,0)) %>%
    select(-c(professional_id, professional_name, `include?`)) %>%
    group_by(organisation_id, patient_id, date, consultation_mode, professional_role) %>%
    summarise(Nr_consultations_per_Pt_day = sum(Nr_consultations_per_Pt_day))

df7 %>% filter(patient_id %in% c(2223, 1250, 1230))

enter image description here

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