i cannot make the cout appear within my switch, i hope someone here could help me

this is the code given to me, aslo please if possible the simplest way of work around, thanks

#include <iostream>

using namespace std;

int main() {
    double fh, cs;

    cout << "Enter Fahrenheit: ";
    cin >> fh;

    cs = (fh - 32) * 5 / 9;
    cout << "Temperature in Celsius: " << cs;

    switch (cs < 40)
    {
    case 1:
        switch (cs <= 0) {
        case 1:
            cout << "\nFreezing weather";
            break;
        }
        break;
    case 2:
        switch ((cs >= 1) < 10) {
        case 1:
            cout << "\nVery Cold weather";
            break;
        }
    case 3:
        switch ((cs >= 11) < 20) {
        case 1:
            cout << "\nCold weather";
            break;
        }
    case 4:
        switch ((cs >= 21) < 30) {
        case 1:
            cout << "\nNormal in Temp";
            break;
        }
    case 5:
        switch ((cs >= 31) < 40) {
        case 1:
            cout << "\nIt's Hot";
            break;
        }


    case 0:
        cout << "\nIt's Very Hot";
        break;
    }

    return 0;
}

CodePudding user response：

the outter switch cs < 40 you can only get 0 if cs >= 40 or 1 if cs < 40, you can not get other cases like 2,3,4,5. Why not just use if statement.

CodePudding user response：

You are using switch the wrong way. Each of the expression written under switch will only evaluate to 0 or 1. So other cases are not reachable. What you are trying to do can be better achieved with if/else.