Question : Write the main method in Solution class.

In the main method, read a String (which may have alphabets along with numeric digits) and print the number of vowels and consonants (any alphabet apart from vowel is a consonant) present in the given String. Note: The output should be printed in the same format as mentioned in the sample output.

Consider below sample input and output:

Input: Welcome123

Output: Number of Vowels: 3 Number of Consonants: 4

My Solution:

import java.util.*;
    public class MyClass
    {
  public static void main(String[] args)
    {
        Scanner sc=new Scanner(System.in);
        String s=sc.nextLine();
        s=s.replaceAll("[^A-Za-z]","");
        String v=s.replaceAll("[^AEIOUaeiou]","");     
        System.out.println("Number of Vowels: " v.length() "\nNumber of Consonants: " (s.length()-v.length()));
    }
}

CodePudding user response：

You can use the following which maybe me easier to read, but this wouldn't be the best solution. Your solution is performant and works.

   if (consonants.contains(str.charAt(i)))
       count  ;
   }

Never just post your assignment, even if you already have a solution.

CodePudding user response：

You can define a pattern for vowels and consonants as a pattern and don't need to modify the input with replace You can name your variables better, You can tidy it up a bit and take care of identation to make it easier to read

Pattern vowel     = Pattern.compile("(?i)[aeiou]");
Pattern consonant = Pattern.compile("(?i)([a-z&&[^aeiou]])");

Scanner scanner = new Scanner(System.in);
String input    = scanner.nextLine();

System.out.println("Number of Vowels: "   vowel.matcher(input).results().count()  
             "\nNumber of Consonants: "   consonant.matcher(input).results().count());

Note: (?i) for case insensitive and a-z&&[^aeiou]] a-z without a,e,i,o,u