As seen in the code that I tried to write, I want to grab a name from the Array list "names" and either add it to groupA or B. I do not need the groups to be even.
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
import java.util.Random;
import java.util.ArrayList;
public class GroupPicker{
public static void main(String[] args) throws FileNotFoundException{
Scanner input = new Scanner(new File("GroupPicker1.txt"));
ArrayList<String> names = new ArrayList<String>();
ArrayList<String> groupA = new ArrayList<String>();
ArrayList<String> groupB = new ArrayList<String>();
Random random = new Random();
while(input.hasNext()){
String nextName = input.next();
names.add(nextName);
}
for (int i = 0; i < names.size(); i ) {
names.get(random.nextInt(groupA.add()));
names.get(random.nextInt(groupB.add()));
}
System.out.println( "\n" "project groups: ");
System.out.println("Group A: " groupA);
System.out.println("Group B: " groupB);
}
}
CodePudding user response:
When I read this problem, two conditions stand out.
- the names must go into one of the lists (meaning not the other) -- you must take it from the names ArrayList
- the names do not need to be even -- you do not need to keep track of which list they are being added to
I would use an enhanced for-loop for ease of use (the less variables the better)
// this cycles through each index of the names ArrayList
for(String singleName : names)
{
// creates a random number
java.util.Random number = new java.util.Random();
// add to groupA if it is an even number and groupB if it is odd
if(number.nextInt(2) % 2 == 0)
groupA.add(singleName);
else
groupB.add(singleName);
}
EDIT AFTER SHOWING MY PROFF XD
For simplicities sake, you could even cut off the % 2 == 0 because 0 and 1 will only ever give you 0 or 1 with that statement. This could look like this:
// true = one list && false = the other
if(number.nextBoolean())
groupA.add(singleName);
else
groupB.add(singleName);
CodePudding user response:
First you have to make sure the random.nextInt()
doesn't give you a too high value, because you only put so much values into names
, but random.nextInt()
will return any int - this could be even negative!
So the easiest way would be this:
- shuffle the
names
list withCollections.shuffle(names)
- put the first half of
names
intogroupA
- with the use ofList.subList
you would not even have to create a new list, just use the returned result. - put the second half of
names
intogroupB
You have to take care about the indexes for the "halfes" - and decide what to do if the number of entries in names
is odd - put one more into groupA
or groupB
.
CodePudding user response:
How can I randomly pull out a String from an array list and put it in another
List<String> names = new ArrayList<>();
Random r = new Random();
nextInt(n)
- returns a value between0 and n-1
inclusiver.nextInt(names.size())
- will get one random index of all possible indices
String name = names.get(r.nextInt(names.size());
List<String> otherList = new ArrayList<>();
otherList.add(name);
Note you can also shuffle a list if required.
Collections.shuffle(names);
Then you can simply iterate across the list, getting names in the new random order.
CodePudding user response:
This is what I would do if I understand your need :
// Scanner input = new Scanner(new File("GroupPicker1.txt"));
String arr[] = new String[] { "A", "B", "C", "D" };
ArrayList<String> names = new ArrayList(Arrays.asList(arr));
ArrayList<String> groupA = new ArrayList<String>();
ArrayList<String> groupB = new ArrayList<String>();
// while(input.hasNext()){
// String nextName = input.next();
// names.add(nextName);
// }
while (!names.isEmpty()) {
for (int i = 0; i < names.size(); i ) {
int random = ThreadLocalRandom.current().nextInt(i, names.size());
boolean randBool = Math.random() < 0.5;
String name = names.get(random);
names.remove(random);
if (randBool){
groupA.add(name);
break;
};
groupB.add(name);
}
}
System.out.println( "\n" "project groups: ");
System.out.println("Group A: " groupA);
System.out.println("Group B: " groupB);