I have 2 dataframes. The first is a summary table that summarizes the accuracy (in descending order) of each industry and its source.
cols = ['industry', 'source', 'accuracy']
df = pd.DataFrame(np.array([
['chemical', 'source B', 0.9],
['chemical', 'source A', 0.7],
['education', 'source A', 0.9],
]), columns=cols)
In the 2nd table, Source A and B have lists of strings in them, and they can be nulls:
cols = ['company', 'industry', 'source A', 'source B']
df2 = pd.DataFrame(np.array([
['company1', 'chemical', np.nan, ['a123', 'b456']],
['company2', 'chemical', ['a555', 'd333'], np.nan],
['company3', 'education', np.nan, ['777', '888']],
]), columns=cols)
For each row/company, I'm supposed to select the first non-null source that has the highest accuracy, which will look something like the following table:
cols = ['company', 'industry', 'which_source', 'source_value']
df3 = pd.DataFrame(np.array([
['company1', 'chemical', 'source B', ['a123', 'b456']],
['company2', 'chemical', 'source A', ['a555', 'd333']],
['company3', 'education', np.nan, np.nan],
]), columns=cols)
For e.g., for company1 and 2, although they're both from the 'chemical' industry, for company2 its source is from source A because its value in source B is null.
And for company3 from 'education' industry, even though there is a value in source B, as source B for 'education' industry doesn't meet some minimum threshold (hence it didn't appear in the df1), it's 'source' and 'source_value' should just be null.
Thanks in advance!
CodePudding user response:
You could melt
, merge
and filter:
df3 = (df2
.melt(['company', 'industry'], var_name='source', value_name='source_value')
.merge(df, how='inner')
.sort_values(by='source_value', key=pd.isna)
.groupby(['company', 'industry'], as_index=False).first()
.assign(which_source=lambda d: d['source'].mask(d['source_value'].isna()))
.drop(columns=['source', 'accuracy'])
)
output:
company industry source_value which_source
0 company1 chemical [a123, b456] source B
1 company2 chemical [a555, d333] source A
2 company3 education None NaN