I want a report xyz.rpt
in the below format
ajsh askj sdjh 54 12
jhgj 765 2839
kjsd sdh sdsdf sdffsdf sdff
5464 765 67 65 76
2356 423 34 45 34
and so on
I want to print first 2 header line also along with the output of awk command.
awk '{if ( $5 < 65 ) print}' > aaa.rpt
CodePudding user response:
One awk
idea:
awk '
FNR<=2 # print 1st 2 lines
FNR>2 && $5 0==$5 && $5<65 # print lines where $5 is numeric and $5 < 65
' xyz.rpt
Or as a one-liner:
awk 'FNR<=2; FNR>2 && $5 0==$5 && $5 < 65' xyz.rpt
This generates:
ajsh askj sdjh 54 12
jhgj 765 2839
2356 423 34 45 34
CodePudding user response:
not as elegant as i hoped
nawk '($5== $(5*( $5<=4^3))) (3>FNR)'
ajsh askj sdjh 54 12
jhgj 765 2839
2356 423 34 45 34
CodePudding user response:
$ awk 'NR<=2 || ($5 0==$5 && $5<65)' file