React useState. Why do the docs advise passing a function with the previous state when setting the s-CodePudding

In the React docs (https://reactjs.org/docs/hooks-reference.html#usestate) it says "If the new state is computed using the previous state, you can pass a function to setState" like so:

const [count, setCount] = useState(initialCount);
setCount(prevCount => prevCount   1)

But why is React suggesting this as a solution when it can be done more succinctly using the count variable like so:

const [count, setCount] = useState(initialCount);
setCount(count   1)

This latter approach works even when working with mutable objects like arrays as in this example:

https://codesandbox.io/s/6b-array-subcomp-event-usestate-props-r032xv

CodePudding user response：

If you have a function that use SetCount twice, without using the prev state, it will setCount only once.

const [count, setCount] = useState(0);
const fun1 = () =>{
   setCount(count   1)
   setCount(count   1)
}
// it will change count to 1 rather than 2

That's why it's recommended to use prev state

CodePudding user response：

The suggestion to use a function is because you're assured to get a reliable previous state in its parameter. On the other side, if you are using a value of a state directly it might happen that you are reading its stale value as react's setState operation is asynchronous and might still have not updated the state.

Here is an example:

function App() {
  const [a, setA] = useState(0);
  const [b, setB] = useState(0);
  useEffect(() => {
    setA(a   2);
    setA(a   2);
  }, []);
  useEffect(() => {
    setB((prev) => prev   2);
    setB((prev) => prev   2);
  }, []);
  return (
    <div>
      <h1>{a}</h1>
      <h1>{b}</h1> 
    </div>
  );
}

a will contain 2 because react will do both setA at once (batch update) therefore reading previous state a once, which is 0 at that moment.

b, however, will have the correct value, 4, as it explicitly uses the previous state provided by the updating functions parameter.