Converting 6-digit Julian date to std date-CodePudding

I have 6-digit Julian dates from DB table, and I am trying to convert them to std date. I get error as the format is not correct. fmt = '%y%m%j'

This is the function I have written:

import datetime
def jdtodatestd (jdate):
    fmt = '%y%m%j'
    datestd = datetime.datetime.strptime(jdate, fmt).date()
    return(datestd)
x = jdtodatestd('122105')
print(x)

In above Julian date "122105":
1 is Century code
22 is Year
105 is 105th day of the year.

I am getting 2012-04-14 as result, but the expected result is 2022-04-15.

CodePudding user response：

Insert jdate = jdate[1:] into your Python function and change format to %y%j

import datetime
def jdtodatestd (jdate):
    jdate = jdate[1:]
    fmt = '%y%j'
    datestd = datetime.datetime.strptime(jdate, fmt).date()
    return(datestd)
x = jdtodatestd('122105')

print(x)
# 2022-04-15