How to match index of an element from a list of list and return result (an element doesnot have simi-CodePudding

I have a very big txt file. I want to read through each line of the file and get an input based on the 3rd element of the file(list).

So, I convert the text file to list and iterate through each element of the list to get my desired output.

This is a part of my txt file:

34566---There was no file in there---Mr. [email protected]

36122---I found the file in [email protected]

64322

28890---I went to see the crowd---Henry [email protected]

44533---The weather made it perfect---Merry [email protected]

This is the code that I used:

value = input("Enter your name:")

filename = open("test.txt", "r")
for line in filename:
  line_num = line.strip('\n').split("---")
  if line_num [2] == value:
     print(line_num[1])
     break

The only problem is the value in the middle doesnot behave as the other elements in the list. So, it is giving an error

IndexError: list index out of range

I don't know how to code to ignore the middle element which doesnot behave as the rest of the elements in the list. Please help me.

CodePudding user response：

You can try this,

value = input("Enter your name:")

filename = open("anotherSix.txt", "r")
for line in filename:
    if line == '\n':
        continue
    line_num = line.strip('\n').split("---")
    if line_num [2] == value:
        print(line_num[1])
        break

As You can see I added only the if line == '\n': continue part which basically skips the empty line

CodePudding user response：

Change your condition to:

if len(line_num) > 2 and line_num [2] == value: