How can I include the delimiter with regex String.split()?-CodePudding

I need to parse the tokens from a GS1 UDI format string:

"(20)987111(240)A(10)ABC123(17)2022-04-01(21)888888888888888"

I would like to split that string with a regex on the "(nnn)" and have the delimiter included with the split values, like this:

[ "(20)987111", "(240)A", "(10)ABC123", "(17)2022-04-01", "(21)888888888888888" ]

Below is a JSFiddle with examples, but in case you want to see it right here:

//  This includes the delimiter match in the results, but I want the delimiter included WITH the value
//  after it, e.g.: ["(20)987111", ...]
str = "(20)987111(240)A(10)ABC123(17)2022-04-01(21)888888888888888";
console.log(str.split(/(\(\d{2,}\))/).filter(Boolean))
//  Result: ["(20)", "987111", "(240)", "A", "(10)", "ABC123", "(17)", "2022-04-01", "(21)", "888888888888888"]

//  If I include a pattern that should (I think) match the content following the delimiter I will 
//  only get a single result that is the full string:
str = "(20)987111(240)A(10)ABC123(17)2022-04-01(21)888888888888888";
console.log(str.split(/(\(\d{2,}\)\W )/).filter(Boolean))
//  Result: ["(20)987111(240)A(10)ABC123(17)2022-04-01(21)888888888888888"]

//  I think this is because I'm effectively mathching the entire string, hence a single result.
//  So now I'll try to match only up to the start of the next "(":
str = "(20)987111(240)A(10)ABC123(17)2022-04-01(21)888888888888888";
console.log(str.split(/(\(\d{2,}\)(^\())/).filter(Boolean))
//  Result: ["(20)987111(240)A(10)ABC123(17)2022-04-01(21)888888888888888"]

I've found and read this question, however the examples there are matching literals and I'm using character classes and getting different results.

I'm failing to create a regex pattern that will provide what I'm after. Here's a JSFiddle of some of the things I've tried: https://jsfiddle.net/6bogpqLy/

I can't guarantee the order of the "application identifiers" in the input string and as such, match with named captures isn't an attractive option.

CodePudding user response：

You can split on positions where parenthesised element follows, by using a zero-length lookahead assertion:

const text = "(20)987111(240)A(10)ABC123(17)2022-04-01(21)888888888888888"
const parts = text.split(/(?=\(\d \))/)
console.log(parts)

CodePudding user response：

Instead of split use match to create the array. Then find 1) digits in parenthesis, followed by a group that might contain a digit, a letter, or a hyphen, and then 2) group that whole query.

(PS. I often find a site like Regex101 really helps when it comes to testing out expressions outside of a development environment.)

const re = /(\(\d \)[\d\-A-Z] )/g;
const str = '(20)987111(240)A(10)ABC123(17)2022-04-01(21)888888888888888';

console.log(str.match(re));