How to check if one string has more than one uppercase character (two or more next to each other) in Java? I've tried:

String word = scanner.nextLine();
for(int i=0;i<word.length();i  ) {
char value = word.charAt(i);
if(Character.isUpperCase(value) && Character.isUpperCase(value 1) {
     System.Out.Print("There is more than one character uppercase");
   }
}

CodePudding user response：

You are adding 1 to value, but value is a char.

I corrected this mistake, it should work now:

public boolean duplicateUpperCase(String word) {
    boolean lastUpperCase;
    for(int i = 0; i < word.length(); i  ) {
        boolean upperCase = Character.isUpperCase(word.charAt(i));
        if (lastUpperCase && upperCase) return true;
        lastUpperCase = upperCase;
    }
    return false;
}

Now to check:

String word = scanner.nextLine();
if (duplicateUpperCase(word)) System.out.println("There is more than one character uppercase");

CodePudding user response：

I think Character.isUpperCase(value 1) does not have the desired outcome in your case, it will simply add 1 to your character value, it will not get the next character in your word String. To get the next character try to use Character.isUpperCase(word.charAt(i 1)).

Doing this, you should also be wary of StringIndexOutOfBounds exception, that's why word.length() > i 1 is being used:

 Scanner scanner = new Scanner(System.in);
 String word = scanner.nextLine();
 for(int i=0;i<word.length();i  ) {
      if(Character.isUpperCase(word.charAt(i))) {
           if( word.length() > i 1 && Character.isUpperCase(word.charAt(i 1)) ){
               System.out.println("There is more than one character uppercase");
           }
       }
 }