How to replace a character within a string in a list?-CodePudding

I have a list that has some elements of type string. Each item in the list has characters that are unwanted and want to be removed. For example, I have the list = ["string1.", "string2."]. The unwanted character is: ".". Therefore, I don't want that character in any element of the list. My desired list should look like list = ["string1", "string2"] Any help? I have to remove some special characters; therefore, the code must be used several times.

hola = ["holamundoh","holah","holish"]
print(hola[0])
print(hola[0][0])
for i in range(0,len(hola),1):
  for j in range(0,len(hola[i]),1):
    if (hola[i][j] == "h"):
      hola[i] = hola[i].translate({ord('h'): None})
print(hola)

However, I have an error in the conditional if: "string index out of range". Any help? thanks

CodePudding user response：

Modifying strings is not efficient in python because strings are immutable. And when you modify them, the indices may become out of range at the end of the day.

list_ = ["string1.", "string2."]

for i, s in enumerate(list_):
    l[i] = s.replace('.', '')

Or, without a loop:

list_ = ["string1.", "string2."]

list_ = list(map(lambda s: s.replace('.', ''), list_))

CodePudding user response：

You can define the function for removing an unwanted character.

def remove_unwanted(original, unwanted):
    return [x.replace(unwanted, "") for x in original]

Then you can call this function like the following to get the result.

print(remove_unwanted(hola, "."))

CodePudding user response：

Use str.replace for simple replacements:

lst = [s.replace('.', '') for s in lst]

Or use re.sub for more powerful and more complex regular expression-based replacements:

import re
lst = [re.sub(r'[.]', '', s) for s in lst]

Here are a few examples of more complex replacements that you may find useful, e.g., replace everything that is not a word character:

import re
lst = [re.sub(r'[\W] ', '', s) for s in lst]