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The below code validated only index 0 I want to check n number of index of array what need to be inc

Time:05-28

The for loop i = 0 checks the password only 0th index I want to check for all index what need to be included.

function validlogin() {
      var user = document.getElementById('user').value;
      var psw = document.getElementById('psw').value;
    
      var items = JSON.parse(localStorage.getItem('login'));
    
      for (let i = 0; i < items.length; i  ) {
    
        if (items[i].username == user && items[i].password == psw)
          {
    
          alert("welcome");
          
          
          }
         
    }
      }

CodePudding user response:

You can use .find to discover the user with the matching username and then validate their password. It looks like you're managing logins on the client-side, definitely don't do this for a production application.

Assuming the login localStorage object looks like [{username: "Among Us", password: "Red is sus"}], here's how you'd do it:

function validlogin() {
    const user = document.getElementById('user').value;
    const psw = document.getElementById('psw').value;
    
    const items = JSON.parse(localStorage.getItem('login'));

    const userData = items.find(({username}) => username === user);

    if (!userData) {
        alert('No user found');
        return;
    }

    if (userData.password !== psw) {
        alert('Incorrect password');
        return;
    }

    alert(`Logged in as ${userData.username}`);
}

CodePudding user response:

You can try something using this logic:

function validlogin() {
  var user = document.getElementById('user').value;
  var psw = document.getElementById('psw').value;

  var items = JSON.parse(localStorage.getItem('login'));

  for (let i = 0; i < items.length; i  ) {

    if (items.username.join('') == user && items.password.join('') == psw)
      {

      alert("welcome");
      
      
      }
     
}
  }
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