I am trying to get a list of the top 100 guests by revenue generated with Elastic Search. To do this I am using a terms
and a sum
aggregation. However it does return the correct values, I wan to return the entire guest
object with the aggregation.
This is my query:
GET reservations/_search
{
"size": 0,
"aggs": {
"top_revenue": {
"terms": {
"field": "total",
"size": 100,
"order": {
"top_revenue_hits": "desc"
}
},
"aggs": {
"top_revenue_sum": {
"sum": {
"field": "total"
}
}
}
}
}
}
This returns a list of the top 100 guests but only the amount they spent:
{
"aggregations" : {
"top_revenue" : {
"doc_count_error_upper_bound" : -1,
"sum_other_doc_count" : 498,
"buckets" : [
{
"key" : 934.9500122070312,
"doc_count" : 8,
"top_revenue_hits" : {
"value" : 7479.60009765625
}
},
{
"key" : 922.0,
"doc_count" : 6,
"top_revenue_hits" : {
"value" : 5532.0
}
},
...
]
}
}
}
How can I get the query to return the entire guests
object, not only the sum amount.
When I run GET reservations/_search
it returns:
{
"hits": [
{
"_index": "reservations",
"_id": "1334620",
"_score": 1.0,
"_source": {
"id": "1334620",
"total": 110.8,
"payment": "unpaid",
"contact": {
"name": "John Doe",
"email": "[email protected]"
}
}
},
... other reservations
]
}
I want to get this to return with the sum
aggregation.
I have tried to use a top_hits
aggregation, using _source
it does return the entire guest
object but it does not show the total amount spent. And when adding _source
to the sum
aggregation it gives an error.
Can I return the entire guest
object with a sum
aggregation or is this not the correct way?
CodePudding user response:
I assumed that contact.name
is keyword
in the mapping. Following query should work for you.
{
"size": 0,
"aggs": {
"guests": {
"terms": {
"field": "contact.name",
"size": 100
},
"aggs": {
"sum_total": {
"sum": {
"field": "total"
}
},
"sortBy": {
"bucket_sort": {
"sort": [
{ "sum_total": { "order": "desc" } }
]
}
},
"guest": {
"top_hits": {
"size": 1
}
}
}
}
}
}