counting consecutive digits in a string-CodePudding

Want to perform the counting of consecutive digits in a string

for example if i have :

s = '[email protected]'
d = '[email protected]'

Expected output for string sis 3. And expected output for string d is 4 since is the max number of consecutive number of consecutive digits inside the string

CodePudding user response：

You can use re.findall to get the consecutive numbers and get the longest group with max with len as key

s = '[email protected]'
digits = re.findall(r"\d ", s)
print(len(max(digits, key=len))) # 3

In case you can have a string with no numbers you can use the default parameter with an empty list for length 0

s = '[email protected]'
digits = re.findall(r"\d ", s)
print(len(max(digits, default=[], key=len))) # 0

CodePudding user response：

The following function is what you looking for:

def max_consecutive_digits(string):
    """
    Returns the maximum number of consecutive digits in a string.
    """
    max_consecutive = 0
    current_consecutive = 0
    for char in string:
        if char.isdigit():
            current_consecutive  = 1
        else:
            if current_consecutive > max_consecutive:
                max_consecutive = current_consecutive
            current_consecutive = 0
    if current_consecutive > max_consecutive:
        max_consecutive = current_consecutive
    return max_consecutive