using tasm/tlink/dosbox in notepad
want: how do i fix 2 digit divide to 2 digits and when if the quotient or remainder answer is also 2 digits? and also what is the possible logic?
my flow is: the flow I made was first I took the first digit of the first number or dividend then I multiplied by 10 to be and I added to the second digit the same as the second number or divisor so that it would be 2 digits in the register after that I'll divide them both.
My Code in notepad :
.model small
.stack 100h
.data
d0 db 0dh,0ah,"Base 03$"
d1 db 0dh,0ah,"Enter Dividend : $" ;string
d2 db 0dh,0ah,"Enter Divisor : $"
d3 db 0dh,0ah,"Display Quotient : $"
d4 db 0dh,0ah,"Display Remainder : $"
.code
main proc ;main program here
mov ax,@data ;initialize ds
mov ds,ax
Div1:
mov ah,09h
lea dx,d0
int 21h
lea dx, d1
int 21h
mov ah,01h
int 21h ;1st Digit
mov ch,al
mov ah,01h
int 21h ;2nd Digit
mov cl,al
or cx,3030h
mov al,ch
mov bl,10h
mul bl ;02*10 = 20
mov bh,al
add bh,cl ;dividend
Div2:
mov ah,09h
lea dx, d2
int 21h
mov ah,01h
int 21h ;1st Digit
mov ch,al
mov ah,01h
int 21h ;2nd Digit
mov cl,al
or cx,3030h
mov al,ch
mul bl
mov dh,al
add dh,cl ;divisor
mov ah,00h
mov al,bh
aad
div dh
mov cx,ax
or cx,3030h
mov ah,09h
lea dx, d3
int 21h
mov ah,02h
mov dl,cl
int 21h
mov ah,09h
lea dx, d4
int 21h
mov ah,02h
mov dl,ch
int 21h
mov ah,4Ch ;end here
int 21h
main endp
end main
Output:
Want Output:
Enter Dividend : 22
Enter Divisor : 02
Display Quotient : 02
Display Remainder : 00
proj
Enter Dividend : 21
Enter Divisor : 02
Display Quotient : 10
Display Remainder : 01
proj
Enter Dividend : 21
Enter Divisor : 11
Display Quotient : 01
Display Remainder : 10
like this calculation but the only i need is the quotient and remainder.
CodePudding user response：
Are you sure about "Want output" ?
Enter Dividend : 22 <<< 8d
Enter Divisor : 02 <<< 2d
Display Quotient : 02 ??? 4d == 11
Display Remainder : 00 <<< 0d
or cx,3030h does nothing to your code because those bits will already have been set, they're part of the ASCII codes from 48 to 50. For conversion purposes you would normally use sub cx,3030h.
Next your multiplication with 10h (16 in decimal) is trying to turn the input into packed BCD (binary coded digits) format. Later the code will use the aad instruction that operates on unpacked BCD and importantly uses 10 as its number base where your program is going for number base 3.
You seem to expect a 2-digit output for both quotient and remainder. Then just printing 2 characters from CL and CH is not enough.
To do
mov ah,01h
int 21h ;1st Digit
mov ch,al
mov ah,01h
int 21h ;2nd Digit
mov cl,al
sub cx,3030h
mov al, 3
mul ch
add al, cl
mov bh,al ;dividend = (D1 * 3) D2
Similarly for the divisor, but put it in BL
mov ah, 0
mov al, bh ; Dividend in BH
div bl ; Divisor in BL
mov cx, ax ; Quotient in CL, Remainder in CH
Ready to print. See my answer I need to show 3 digit answer Using tasm/tlink/dosbox in notepad
CodePudding user response：
Your algorithm for conversion is confused:
first I took the first digit of the first number or dividend then I multiplied by 10 to be and I added to the second digit
In fact you have multiplied the first digit by 16 because of mov bl,10h.
See also questions 8086 simple decimal addition from user input or How to convert an ASCII char to a decimal representation?.
Or use some more general method to how to convert input string with more than two decimal numbers to a binary value. See the macro LodD for inspiration.
What you need is Turbo Debugger which allows to execute you program instruction by instruction and watch if the registers change as expected.