Reorder output from Awk, sum first-CodePudding

I have the following variable:

results=$(find . -name "$1" -type f | awk '{n  ;print}END{print n " matches found"}')

This is the output I'm getting:

bash$ ./find-file.sh requirements.txt
find: `./LogFiles/WMI/RtBackup': Permission denied
./project-h-squad/requirements.txt: line 11: python-dotenv==0.17.1: command not found
./project-h-squad/requirements.txt
./team-portfolio/requirements.txt
2 matches found

The only problem is that I want to display 2 matches found at the start or the top and the files to be displayed right after. How can I tweak results to accomplish this?

CodePudding user response：

There's no need to use awk for this; just use bash arrays:

#!/usr/bin/env bash

readarray -d '' -t results < <(find . -name "$1" -type f -print0)
printf "%d matches found.\n" "${#results[@]}"
printf "%s\n" "${results[@]}"

The readarray line will robustly store the files returned by find in an array (By using a 0 byte between filenames instead of newline, annoying files with newlines in the name won't break things), prints out the length of the array, and then its contents.

CodePudding user response：

Does this solve your problem?

results=$(find . -name "$1" -type f | awk '{n[$0]=$0} END{print length(n) " matches found"; for(result in n){print n[result]}}')

N.B. "2 matches found" will be printed first but the array isn't sorted, so "team-portfolio/requirements.txt" might be printed before or after "project-h-squad/requirements.txt"