I would like to match numbers greater than or equal to 1001(or '1001'). I tried the following pattern "^(^[1-9][0-9]{3,4}$)$"
. It matches from 1000 and above.
CodePudding user response:
(?!^1000$)^[1-9]\d{3,}$
Short Explanation
(?!^1000$)
Except the number1000
^[1-9]\d{3,}$
Match 4 and more length numbers
JavaScript Example
let regex = /(?!^1000$)^[1-9]\d{3,}$/;
console.log(regex.test("1000"));
console.log(regex.test("1001"));
console.log(regex.test("10000"));
console.log(regex.test("99995555"));
See the regex demo