Is there a simpler method for getting the two digit year?-CodePudding

EDIT: Forced to use 2008 R2

I need to get the two digit year to appended to an invoice number (for simplicity sake I am using a test variable). Previously I only needed the month and day appended but the customer is now asking for the two digit year.

My Method: REPLACE SUBSTRING STR YEAR(variable DATETIME)

REPLACE((SUBSTRING(STR (Year(@Date),4),3,2)), ' ', '0')**

My code:

DECLARE @TestVariable AS VARCHAR(100),
@Date as datetime = GetDate()
SET @TestVariable = '1234' 
  REPLACE(STR(MONTH(@Date), 2), ' ', '0') 
  REPLACE(STR(DAY(@Date), 2), ' ', '0') 
   REPLACE((SUBSTRING(STR (Year(@Date),4),3,2)), ' ', '0')

PRINT @TestVariable

CodePudding user response：

Honestly, just don't work with 2 digit years any more; learn the lessons of last century's mistake and use 4 digits.

If you "have" to, then you could use CONVERT with a style code, and then just replace the characters with an empty string:

DECLARE @TestVariable varchar(100) = '1234',
        @Date datetime = GETDATE();

SELECT @TestVariable   REPLACE(CONVERT(varchar(8),@Date, 1),'/','');

CodePudding user response：

You can simplify the whole process, not just the year portion. Using FORMAT you can accomplish this easily.

DECLARE @TestVariable AS VARCHAR(100) = '1234' 
    , @Date as datetime = GetDate()

Select @TestVariable   FORMAT(@Date, 'MMddyy')

CodePudding user response：

select replace(convert(varchar(20),@date,1)'/','') --or any other you need

See the docs

CodePudding user response：

I'll echo others' sentiment of "do you really have to use a two-digit year"? But if you have to, I like this sort of thing

set @TestVariable = '1234'
      right('0'   cast(month(@date)      as varchar(2)), 2)
      right('0'   cast(day(@date)        as varchar(2)), 2)
      right('0'   cast(year(@date) % 100 as varchar(2)), 2);

To talk through the general approach, I'm using right('0', «something», 2) as a means to zero pad to two places, using cast(«something» as varchar(2)) to get a string instead of a number (so implicit conversion doesn't just add zero and the relevant datepart), and finally year(@date) % 100 to get the last two digits of the date.