I have a database with 3 tables. In table country
I have id
and name
columns. The sport
table also has id
and name
columns. Finally, the table match
has id
, player1
, and player2
(that are ids of country that play one against other), winner_id
(id of country that won the match) and sport_id
of the sport which was played.
I want to show the sport per country with the least wins. It should look like this:
Country | Sport | Wins |
---|---|---|
France | Basketball | 2 |
How can I construct this query? I'm using SQL Server.
CodePudding user response:
You need to first cross-join the sports with the countries, then get the total.
Then you can use a row-number approach to get the bottom country in each sport
SELECT
c.Country,
c.Sport,
c.Wins
FROM (
SELECT
c.name Country,
s.name Sport,
COUNT(m.winner_id) Wins,
ROW_NUMBER() OVER (PARTITION BY s.sport_id, s.name ORDER BY COUNT(m.winner_id)) rn
FROM country c
CROSS JOIN sport s
LEFT JOIN [match] m
ON s.sport_id = m.sport_id AND m.winner_id = c.country_id
GROUP BY
s.sport_id,
s.name,
c.country_id,
c.name
) c
WHERE c.rn = 1;
CodePudding user response:
I want to note that the used wording with least wins
is not clear, in my solution with least wins
means most matches played with least wins
.
To get this ranking, we need to know how many matches a country has played in each sport and how many of those have been won.
SELECT
country.name AS country,
sport.name AS sport,
sport_wins.wins
FROM
country
OUTER APPLY (
SELECT TOP 1
t.match_count,
COALESCE(t.wins, 0) AS wins,
t.sport_id
FROM (
SELECT
COUNT(*) AS match_count,
m_c.sport_id,
t.wins
FROM match m_c
OUTER APPLY (
SELECT
COUNT(*) AS wins,
match.sport_id
FROM match
WHERE country.country_id = match.winner_id
AND match.sport_id = m_c.sport_id
GROUP BY match.sport_id
) t
WHERE country.country_id IN (m_c.player1, m_c.player2)
GROUP BY m_c.sport_id, t.wins
) t
ORDER BY t.wins ASC, t.match_count DESC
) sport_wins
JOIN sport ON sport.sport_id = sport_wins.sport_id
Please, check a demo.