Is there a way for me to add an exception to my code? (CLOSED)-CodePudding

So i have this code:

x=1
while x <= 2:
    text=input("> ")
    print(f"running {text}....")
    x=x 0
    if text=="quit":
        quit()
    if text=="clear":
        import os
        os.system("clear")

So i wanted to know if there was a way for me to tell python "hey could you please not print "running..." on these two words, clear and quit?" And well i tried all i could think of, and it either: ignored it, or it threw up an error telling me to screw off, could you guys maybe help me?

CodePudding user response：

Sure you can. Perhaps the easiest way to use the if/elif/else in your code.

Code:

x = 1
while x <= 2:
    text = input("> ")
    x = x   0
    if text == "quit":
        quit()
    elif text == "clear":
        import os
        os.system("clear")
    else:
        print(f"running {text}....")

Output:

>>> python3 test.py 

> foo
running foo....
> quit

CodePudding user response：

It's pretty similar to fizzbuzz. That's probably why it seems hard to come up with a "nice" solution.

text=input("> ")
if text != "quit" && text != "clear":
    print(f"running {text}....")

I was just about to add an alternative and better approach with elif and else, but @milanbalazs was faster. :)

When you expand the application, this approach might be a good option:

nonprintables = ["quit", "clear"]
while x <= 2:
    text=input("> ")
    if not text in printables:
        print(f"running {text}....")