I want to regex match any alphabet/number/underscore character as well as double colons in a string if the first word contains "Blue".
For example,
Blue Red Yellow //return Red
Blue Red::Orange Yellow //return Red::Orange
Purple Red Yellow //return nothing
Blue R_E_D //return R_E_D
Red Blue //return nothing
Blue.ish Yellow //return Yellow
I tried /Blu\S \s (\w )/
and it's working for all cases except the ::
case. How can I add a match after checking for w
to match double colons as well IF present without having to mandate my regex to only match if there is a ::
present as well.
CodePudding user response:
You can use a capture group and repeat the word char or :
^Blue\b\S*\h ([\w:] )
The pattern matches:
^
Or use\b
if not at the startBlue\b\S*
Match the wordBlue
and optional non whitspace cahrs\h
Match 1 spaces([\w:] )
Capture 1 word chars or:
in group 1
Or using \K
to clear the match buffer:
^Blue\b\S*\h \K[\w:]
If the word can not start with a colon but should have ::
in between and Bluebird
should also match as noted in the comments by @ikegami:
\bBlue\S*\h \K\w (?:::\w )*