So at runtime I get an Hlist of Hlists which looks like:
(2 :: HNil) :: (1001 :: HNil) :: (1001 :: HNil) :: HNil
Here the type of the resultant Hlist is :
(Int :: HNil) :: (Long :: HNil) :: (Long :: HNil) :: HNil
but this could have been any other type at runtime. For example, it could have been
(Int :: HNil) :: (String :: HNil) :: HNil
Is there a way to flatten this HList like so:
2 :: 1001 :: 1001 :: HNil
with the following type:
Int :: Long :: Long :: HNil
CodePudding user response:
You can do it applying functional operations to HList. Take a look to how Poly works. First, we declare the Poly for (Int::HNil) and (Long::HNil):
import shapeless._
object myPoly extends Poly1 {
implicit val tupleIntCase: Case.Aux[(Int :: HNil), Int] =
at(position => position.head)
implicit val tupleLongCase: Case.Aux[(Long :: HNil), Long] =
at(position => position.head)
}
and using the map function you can extract and flatten the HList:
((2 :: HNil) :: (1001L :: HNil) :: (1001 :: HNil) :: HNil).map(myPoly)
It gives the desired result:
2 :: 1001 :: 1001 :: HNil
Note that the resulting type here is:
Int :: Long :: Int :: HNil